**Question No.2**

**For the given system of equations find the value of “y” using the Crammer Rule.**

**2x+3y+z=2**

**x+3y+z=1**

**3x+y+z=3**

**Solution**

** Here**

**2x+3y+z=2**

**X+3y+z=1**

**3x+y+z=3**

** We have to find ‘y’**

** So,**

**=2(3-1)-3(1-3)+1(1-9) = 2(2)-3(-2)+1(-8)=4+6-8=2**

**=2(1-3)-2(1-3)+1(3-3) = 2(-2)-2(-2)+1(0)=-4+4=0**

** So, by Cramer’s Rule**